Total head at a section is H = p/(rho g) + z + v^2/(2g). If the local pressure head is 12 m, elevation is 3 m, velocity head is 2 m, what is H?

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Multiple Choice

Total head at a section is H = p/(rho g) + z + v^2/(2g). If the local pressure head is 12 m, elevation is 3 m, velocity head is 2 m, what is H?

Explanation:
Total head is the sum of the three heads: pressure head, elevation head, and velocity head. Here, the pressure head is 12 m, the elevation head is 3 m, and the velocity head is 2 m. Add them: 12 + 3 + 2 = 17 m. This represents the energy per unit weight carried by the fluid along a streamline (neglecting losses). So the total head is 17 meters.

Total head is the sum of the three heads: pressure head, elevation head, and velocity head. Here, the pressure head is 12 m, the elevation head is 3 m, and the velocity head is 2 m. Add them: 12 + 3 + 2 = 17 m. This represents the energy per unit weight carried by the fluid along a streamline (neglecting losses). So the total head is 17 meters.

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