A nozzle with Cd = 0.98 discharges into atmosphere. If head h = 5 m and nozzle area A = π(0.025)^2 ≈ 0.0019635 m^2, compute Q.

Prepare for the Intermediate Hydraulics Test with our comprehensive study resources. Explore quizzes featuring multiple-choice questions, in-depth explanations, and hints. Ace your exam with confidence!

Multiple Choice

A nozzle with Cd = 0.98 discharges into atmosphere. If head h = 5 m and nozzle area A = π(0.025)^2 ≈ 0.0019635 m^2, compute Q.

Explanation:
The flow through a nozzle into the atmosphere follows the orifice discharge relationship: Q = Cd × A × sqrt(2 g h). Here Cd accounts for losses, A is the nozzle area, h is the head, and g is gravity. Compute the terms: - A = π(0.025)^2 = 0.0019635 m^2 - sqrt(2gh) = sqrt(2 × 9.81 × 5) = sqrt(98.1) ≈ 9.9046 m/s Then Q = 0.98 × 0.0019635 × 9.9046 ≈ 0.0191 m^3/s. So the discharge is about 0.0191 m^3/s.

The flow through a nozzle into the atmosphere follows the orifice discharge relationship: Q = Cd × A × sqrt(2 g h). Here Cd accounts for losses, A is the nozzle area, h is the head, and g is gravity.

Compute the terms:

  • A = π(0.025)^2 = 0.0019635 m^2

  • sqrt(2gh) = sqrt(2 × 9.81 × 5) = sqrt(98.1) ≈ 9.9046 m/s

Then Q = 0.98 × 0.0019635 × 9.9046 ≈ 0.0191 m^3/s.

So the discharge is about 0.0191 m^3/s.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy